Question

Question #5bbf0

Answer 1

See Below

Explanation:

Right side->`=cosx(csc^2 x-1)`

`=cosx(cot^2x)`--> `cot^2 x= csc^2x-1`

`=sinxcotx(cot^2x)`---> `cosx=sinxcotx`

`=sinx cot^3x`

`= 1/cscx cot ^3x`

`=cot^3x/cscx`

`=` Left Side