How do you graph #r=12/(-4costheta+6sintheta)#?

2 Answers
Mar 22, 2018

Draw a line with a #y#-intercept of #2# and a gradient of #2/3#

Explanation:

Multiply each term by #(-4costheta+6sintheta)#

#r(-4costheta+6sintheta)=12#

#-4rcostheta+6rsintheta=12#

#-2rcostheta+3rsintheta=6#

#rcostheta=x#
#rsintheta=y#

#-2x+3y=6#
#y=(2x+6)/3=(2x)/3+2#

Draw a line with a #y#-intercept of #2# and a gradient of #2/3#

Mar 22, 2018

I use the Desmos Graphing Calculator; it is a free online graphing tool that anyone can use.

Explanation:

One thing that I do not like about the calculator is that it requires that polar equations be in the form #r = f(theta)#; it will graph your equation very well but it will not graph something like the following:

#r^2 = r sin(theta) + 5#

It does not have this requirement for Cartesian equations.

I like that you can graph multiple equations and you can select the colors that you like.

I wish that it did 3d plots but you can't have everything for free.

You can make a user-id and I have one but I found that you have all of the features except the ability to save your work without logging on.