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How do you write the equations of a line passing through (2,5) and (1,3) in standard form?

1 Answer

Oct 20, 2015

$- 2 x + y = 1$ $-2x+y=1$

Explanation:

$x_{1} = 2$ $x_1=2$
$y_{1} = 5$ $y_1=5$
$x_{2} = 1$ $x_2=1$
$y_{2} = 3$ $y_2=3$

$(y - y_{1}) = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$ $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$
$(y - 5) = \frac{3 - 5}{1 - 2} (x - 2)$ $(y-5)=(3-5)/(1-2)(x-2)$
$(y - 5) = \frac{- 2}{- 1} (x - 2)$ $(y-5)=(-2)/(-1)(x-2)$
$(y - 5) = \frac{2}{1} (x - 2)$ $(y-5)=2/1(x-2)$
$y - 5 = 2 x - 4$ $y-5=2x-4$
$y = 2 x - 4 + 5$ $y=2x-4+5$

$y = 2 x + 1$ $y=2x+1$
$- 2 x + y = 1$ $-2x+y=1$

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