How do you write the equations of a line passing through (2,5) and (1,3) in standard form?
1 Answer
Oct 20, 2015
-2x+y=1−2x+y=1
Explanation:
(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)(y−y1)=y2−y1x2−x1(x−x1)
(y-5)=(3-5)/(1-2)(x-2)(y−5)=3−51−2(x−2)
(y-5)=(-2)/(-1)(x-2)(y−5)=−2−1(x−2)
(y-5)=2/1(x-2)(y−5)=21(x−2)
y-5=2x-4y−5=2x−4
y=2x-4+5y=2x−4+5
y=2x+1y=2x+1
-2x+y=1−2x+y=1