Question

How do you write `(x-17.09)^2+(y-1.53)^2=1.03^2` into the general form?

Answer 1

This is the equation of a circle that is offset such that the centre is at

`(x,y)->(17.09,1.53)` and it has a radius of length `1.03`

This basically is already in general form for a circle.

Explanation:

Standard form is `(x-h)^2+(y-k)^2=r^2`

Where `r` is the radius and `(h,k)` is the centre.