Question

How many liters are contained in 1.75 mol of F2 gas at STP?

Answer 1

The answer is `39.2L`.

The gas laws tell us that all ideal gasses behave identically under the same conditions. At STP, the molar volume of any ideal gas is equal to `V_(mol ar) = 22.4L`, which means that `1` mole of any gas at STP will occupy exactly `22.4 L`.

Therefore we can determine the volume occupied by any number of moles of any ideal gas at STP by using

`n = V/V_(mol ar)`, which results in `V = n * V_(mol ar) = 1.75 mo l es* (22.4 L)/(1 mol e) = 39.2 L`