Question

Question #7c9bd

Answer 1

The answer is pH = `11.97`.

The balanced chemical equation is

`KOH_((s)) + H_2O_((l)) -> K_((aq))^+ + OH_((aq))^-`

Since `KOH` is a strong base, it will completely dissociate into `K^+` and `OH^-` ions; this means that the concentration of both `K^+` and `OH^_` will be equal to the starting concentration of `9.28 * 10^-3M`.

We know that pH = `14 - pOH`, which means that we need to determine the **pOH ** first

`pOH = -log([OH^-]) = -log(9.28 * 10^-3) = 2.03`

Therefore, the pH is equal to `pH = 14 - 2.03 = 11.97`