How do you integrate $\frac{x^{2}}{x^{3} + 1}$ $x^2/(x^3+1)$ ?

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Answer 1 · 2015-03-16T11:07:49

$\int \frac{x^{2}}{x^{3} + 1} d x = \frac{1}{3} \int \frac{3 x^{2}}{x^{3} + 1} d x$ $int x^2/(x^3+1) dx = 1/3int(3x^2)/(x^3+1)dx$

Now you have $(f'(x))/f(x)$ form.

Integral is : $1/3ln(|\x^3+1|)+C$

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