How do you multiply ${(- 5 x^{4} y^{2})}^{3}$ $(-5x^4y^2)^3$ ?

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Answer 1 · 2015-04-10T11:05:06

First of all, refer to the Index law of ${(a^{m})}^{n} = a^{m n}$ $(a^m)^n=a^(mn)$

This means when there's a power of a power, the powers are multiplied. e.g. ${(2^{4})}^{2} = 2^{4 \times 2} = 2^{8}$ $(2^4)^2=2^(4xx2) = 2^8$

${(- 5 x^{4} y^{2})}^{3}$ $(-5x^4y^2)^3$ :

We have to multiply all the powers of the values within the bracket by 3 thus.

${(- 5 x^{4} y^{2})}^{3}$ $(-5x^4y^2)^3$ = ${(- 5)}^{3} x^{4 \times 3} y^{2 \times 3} = - 125 x^{12} y^{6}$ $(-5)^3x^(4xx3)y^(2xx3)=-125x^12y^6$

$- 125 x^{12} y^{6}$ $-125x^12y^6$ is thus the answer.

How do you multiply (−5x4y2)3(-5x^4y^2)^3?