How do you find a slope of a line parallel to the graph of y=-2/3x - 1y=−23x−1?

1 Answer
Pris
Apr 11, 2015

Parallel lines have the same slope all the time, only different y-intercept.
Thus, the slope of the line parallel to the graph of y=-2/3x-1y=−23x−1 is m=-2/3m=−23.

Graph of y= -2/3x-1y=−23x−1
graph{-2/3x-1 [-10, 10, -5, 5]}

Graph of y=-2/3x-2y=−23x−2
graph{-2/3x-2 [-10, 10, -5, 5]}

The slope of both graphs of y=-2/3-1y=−23−1 and y=-2/3x-2y=−23x−2 remains at m=-2/3m=−23.

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