What is the most likely mechanism and the product from the reaction between 2-chloro-2-methylpentane and sodium ethoxide in ethanol?
1 Answer
Apr 24, 2015
Formation of 2-pentene via E1 elimination.
A tertiary halide reaction with a strong base in a protic solvent favors the formation of a tertiary carbocation and subsequent protonation of the base leading to the most substitute alkene.
