Question #885cc Chemistry Chemical Equilibrium Ksp 1 Answer il maestro Apr 27, 2015 [OH−] =10−5 From Ksp of Cu(OH)2, it starts precipitating at: 2.2⋅10−20 = [Cu2+]*[OH−]2 [OH−]=√0.22⋅10−20=0.46⋅10−10 and from Ksp of Mg(OH)2, it starts precipitating at 6.3⋅10−10 =[Mg2+]*[OH−]2 [OH−]=√1.26⋅10−10 =1.12⋅10−5 therefore at [OH−]=10−5 all Cu(OH)2 is precipitated and all Mg(OH)2 is in solution Answer link Related questions How can you use the solubility product constant to calculate the solubility of a sparingly... Question #f5130 What is Ksp? How can Ksp be calculated? How is Ksp related to molarity? Question #da59d Question #71344 Question #17cc3 What is the molar solubility of magnesium fluoride in a solution that is 0.1 M sodium fluoride? (a) How much aluminium hydroxide will dissolve in 500ml of water at 25∘C given that... See all questions in Ksp Impact of this question 2095 views around the world You can reuse this answer Creative Commons License