How do you solve #abs(5x + 2) <= 0#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Alberto M. May 11, 2015 #x=-2/5# The Abs value is always positive or 0, so #abs(5x+2)<=0 <=> abs(5x+2)=0 <=> 5x+2=0 <=> x=-2/5# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1411 views around the world You can reuse this answer Creative Commons License