Question

How do you solve `x^2+3x+2` by completing the square?

Answer 1

The answer is `x=-1` and `x=-2`

`x^2+4x+4-x-2=0 => (x+2)^2-(x+2)=0`

So you know one answer is `x=-2`

Now you can divide the polynomial by its factor `(x+2)` and you have

`x+2 - 1 = 0 => x=-1`