How do you solve #abs(x+4)<0#?
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"Suppose that I don't have a formula for #g(x)# but I know that #g(1)
= 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
May 24, 2015
You don't need to salve it. It is easily impossible.
This is because an absolute value can't be less than zero!
