How do you find the derivative of #x^2+1#?

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Answer 1 · 2015-05-28T21:06:43

Simply using the power rule #(x^a)'=ax^(a-1)#:
#(x^2-1)'=(x^2)'+1'=2x+0=2x#

Answer 2 · 2018-04-01T10:35:07

#2x#

Using the power rule:

#f(x)=x^n -> f'(x)=nxxx^(n-1)#

#d/dx (x^2+1)#

#-> 2x^1#

#-> 2x#

Anything without an #x# will always give an answer of #0#