Question

How do you find `2p^2 + 3p - 4` less `- 2p^2 - 3p + 4`?

Answer 1

`2p^2 + 3p - 4` less `- 2p^2 - 3p + 4` is
`2(2p^2+3p-4)`.

Explanation:

The expression you wrote means `2p^2 + 3p - 4 - (- 2p^2 - 3p + 4)=`
`2p^2+3p-4+2p^2+3p-4=`
`4p^2+6p-8=`
`2(2p^2+3p-4)`.