Given: $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2+ sqrt(-3x+1)$ , $q (x) = \frac{5 x}{x + 2}$ $q(x) = (5x)/(x+2)$ , and $m (x) = ∣ ∣ 7 - x^{2} ∣ ∣ + x$ $m(x) = abs(7 - x^2) + x$ , how do you find m(3)?

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Answer 1 · 2015-06-15T22:08:09

$m (3) = ∣ ∣ 7 - 3^{2} ∣ ∣ + 3 = 5$ $m(3) = abs(7-3^2) + 3 = 5$

I don't know what you need $f (x)$ $f(x)$ and $q (x)$ $q(x)$ for , you just want to evaluate $m (x)$ $m(x)$ in $x = 3$ $x=3$

Given: f(x) = 2+ sqrt(-3x+1)f(x)=2+√−3x+1f(x) = 2+ sqrt(-3x+1), q(x) = (5x)/(x+2)q(x)=5xx+2q(x) = (5x)/(x+2), and m(x) = abs(7 - x^2) + xm(x)=∣∣7−x2∣∣+xm(x) = abs(7 - x^2) + x, how do you find m(3)?