How do you write y=4/3x+2/3 in standard form?

1 Answer
Jun 28, 2015

4x-3y=-2

Explanation:

The standard form of a linear equation is:
Ax + By = C
A can not be negative. A, B and C should all be integers.

The first thing we should do is move the x over to the left part of the equation. You can do this by substracting 4/3x from both parts:
y - 4/3x = 4/3x + 2/3 - 4/3x
y - 4/3x = 2/3

By reordering, you get:
-4/3x + y = 2/3

Now we need to make sure that the number that's before the x (A) is positive. You can do this by multiplying both parts by -1:

-1*(-4/3x + y) = -1*2/3
4/3x - y=-2/3

Now, all we need to do is make A, B and C integers. You can always do this by multiplying by the LCM of all the denominators (3, 1 and 3). This LCM is 3:

3*(4/3x - y)=3*(-2/3)
4x-3y=-2