How do you solve #4x² - 36 = 0#?

Question

7205 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-30T21:37:48

#x=3#

Start my moving #-36# to the other side, so it would look like this:

#4x^2=36#

Then, divide all sides by 4:

#x^2=9#

And finally, the root of 9 is...:

#x=3#

There you have it:)