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Answer 1 · 2015-09-13T10:49:49

The gold foil sheet is $1.07 \cdot 10^{- 4} c m$ $1.07*10^-4 cm$ thick.

To get this one first has to divide the mass of the gold sheet by the density of gold to get the volume:

$\frac{Mass of Gold}{Density} = Volume$ $("Mass of Gold")/("Density") = "Volume"$

$V o l u m e = \frac{6.5 \cdot 10^{- 3} g}{19.32 \frac{g}{c m^{3}}}$ $Volume = (6.5*10^-3 g)/(19.32 g/(cm^3))$

$V o l u m e = (6.5 \cdot 10^{- 3} g) \cdot (\frac{1}{19.32}) \frac{c m^{3}}{g}$ $Volume = (6.5*10^-3 g)*(1/19.32) (cm^3)/g$

*This is because the division was changed to multiplication so that the $c m^{3}$ $cm^3$ is at the top and the grams cancel.

Therefore: $Volume = 3.35 \cdot 10^{- 4} c m^{3}$ $"Volume" = 3.35*10^-4cm^3$

$\frac{Volume}{Area} = Thickness$ $("Volume")/("Area") = "Thickness"$

Thus: Thickness = $\frac{3.35 \cdot 10^{- 4} c m^{3}}{3.12 c m^{2}}$ $(3.35*10^-4cm^3)/(3.12cm^2)$

Thickness = $1.07 \cdot 10^{- 4} c m$ $1.07*10^-4cm$

Hope I helped :)