How do you find the average rate of change for the function $s(t)=4.5t^2$ on the indicated intervals [6,6+h]?

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Answer 1 · 2015-09-13T13:58:18

It is $4.5*(h+12)$

It is

$(Δs)/(Δt)=(s(6+h)-s(6))/(6+h-6)=4.5*((6+h)^2-6^2)/(6+h-6)= 4.5/h*(36+12h+h^2-36)=4.5*((h^2+12h)/h)=4.5*(h+12)$

How do you find the average rate of change for the function s(t)=4.5t^2s(t)=4.5t^2 on the indicated intervals [6,6+h]?