How do you find the area of a triangle whose vertices are (0, 5), (2, -2), and (5, 1)?

1 Answer
Sep 28, 2015

13.50

Explanation:

if the three vertices of a triangle are #(x_1,y_1),(x_2,y_2) & (x_3,y_3) #
then the area of triangle is
# a = 1/2*(x_1*(y_2-y_3)+x_2*(y_3-y_1)+x_3*(y_1-y_2))#

so

#a = 1/2*(0*(-2-1)+2*(1-5)+5*(5-(-2))) = 13.50#