How do you find the exact values of cot, csc and sec for 30 degrees?

Question

6558 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-03T11:31:24

sin#30^0# = 1/2, cos #30^0# = (#sqrt# 3) /2 and tan #30^0# = 1 / #sqrt# 3
Now csc #30^0#= 2,sec #30^0# = 2/#sqrt# 3 and cot #30^0# = #sqrt#3