How do you solve #x^2+10=11#?

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Answer 1 · 2015-10-15T01:54:13

#+-1#

Subtract #10# form both sides

#x^2+10-10=11-10#

#x^2=1#

Take the square root of both sides

#sqrt(x^2)=+-sqrt(1)#

#x=+-1#

Remember we have to have plus or minus #1# because
#1^2=1# and #(-1)^2=1#