How do you solve $x^2+10=11$ ?

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Answer 1 · 2015-10-15T01:54:13

$+-1$

Subtract $10$ form both sides

$x^2+10-10=11-10$

$x^2=1$

Take the square root of both sides

$sqrt(x^2)=+-sqrt(1)$

$x=+-1$

Remember we have to have plus or minus $1$ because
$1^2=1$ and $(-1)^2=1$

How do you solve x^2+10=11x^2+10=11?