Question

How do you find the derivative of `3/2 t^(1/2)`?

Answer 1

`(3sqrtt)/(4t)`

Explanation:

`y'=3/2*1/2*t^(1/2-1) = 3/4 t^(-1/2) = 3/(4t^(1/2)) = 3/(4sqrtt)*sqrtt/sqrtt=(3sqrtt)/(4t)`