A train of weight, 3.7x106 N is moving at a speed of 40.8 m/s. Determine its Kinetic energy ?

1 Answer

314,24MJ314,24MJ

Explanation:

E_k=1/2mv^2Ek=12mv2

=1/2(W/g)v^2=12(Wg)v2 here W is the weight of the train, so that we could calculate for its mass

inserting the variables,
=1/2((3,7xx10^6)/(9,8))(40,8)^2=12(3,7×1069,8)(40,8)2

=314,24MJ=314,24MJ