How do you factor $- 4 x^{4} + 8 x^{3} - 20 x$ $-4x^4+8x^3-20x$ ?

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How do you factor $- 4 x^{4} + 8 x^{3} - 20 x$ $-4x^4+8x^3-20x$ ?

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Answer 1 · 2015-11-10T02:04:29

$- 4 x (x^{2} (x - 2) + 5)$ $-4x(x^2(x-2)+5)$

Explanation:

Look for anything that can be factored from everything like a $- 4 x$ $-4x$
so $- 4 x^{4} + 8 x^{3} - 20 x$ $-4x^4+8x^3-20x$ becomes $- 4 x (x^{3} - 2 x^{2} + 5)$ $-4x(x^3-2x^2+5)$

At this point look to see if $x^{3} - 2 x^{2} + 5$ $x^3-2x^2+5$ can be factored, it looks like an $x^{2}$ $x^2$ can be taken from $x^{3} - 2 x^{2}$ $x^3-2x^2$ which becomes: $x^{2} (x - 2)$ $x^2(x-2)$

This gives the final answer:
$- 4 x (x^{2} (x - 2) + 5)$ $-4x(x^2(x-2)+5)$

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How do you factor $- 4 x^{4} + 8 x^{3} - 20 x$ $-4x^4+8x^3-20x$ ?

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Explanation:

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How do you factor $- 4 x^{4} + 8 x^{3} - 20 x$ $-4x^4+8x^3-20x$ ?