How do you solve $\frac{x + 3}{x - 4} \leq 2$ $(x+3)/(x-4) ≤ 2$ ?

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Answer 1 · 2015-11-13T12:28:56

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Bring $x - 4$ $x-4$ to the other side and solve it.

Separate x and numbers on different side to get the answer.

:)

How do you solve (x+3)/(x-4) ≤ 2x+3x−4≤2(x+3)/(x-4) ≤ 2?