What is the equation of the line passing through #(4,2) # with slope #m= -4/5 #?
1 Answer
Nov 17, 2015
I'm assuming you want it in slope-intercept form.
Explanation:
Slope intercept form is written as y=mx+b, where m is the slope, b is the y intercept, and x and y stay written as x and y in the final equation.
Since we already have the slope, our equation is now:
y=(-4/5)x+b (because m represents the slope so we plug the slope's value in for m).
Now we must find the y intercept. In order to do this, we simply use the point given, by plugging in 4 for x and 2 for y. It looks like:
2=(4/5)(4)+b
2=16/5+b
b=-4/5
Now we plug in -4/5 for b and -4/5 for m and we get our final equation:
y=(-4/5)x-4/5