How do you solve the inequality $7 \frac{x}{3} < 2$ $7x/3 < 2$ ?

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How do you solve the inequality $7 \frac{x}{3} < 2$ $7x/3 < 2$ ?

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Answer 1 · 2015-12-01T05:06:44

The answer would be : $x < \frac{6}{7}$ $x<6/7$

Explanation:

First, we divide 7 on both sides, since 7 is multiplying $\frac{x}{3}$ $x/3$ . We get: $\frac{x}{3} < \frac{2}{7}$ $x/3<2/7$ . Then, we multiply 3 on both sides, getting: $x < 3 \frac{2}{7}$ $x<3 2/7$ which can become: $x < \frac{6}{7}$ $x<6/7$ .

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How do you solve the inequality $7 \frac{x}{3} < 2$ $7x/3 < 2$ ?

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