What is the slope intercept form of the line passing through $(4, - 2)$ $(4,-2)$ with a slope of $- \frac{1}{3}$ $-1/3$ ?

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Answer 1 · 2015-12-12T03:58:36

$y = - \frac{1}{3} x - \frac{2}{3}$ $y=-1/3x-2/3$

The slope intercept form is

$y = m x + b$ $y=mx+b$

Where m is the slope and b is the y intercept
So you what m is because you are given the slope

$m = - \frac{1}{3}$ $m=-1/3$

So put that into the equation

$y = - \frac{1}{3} x + b$ $y=-1/3x+b$

Now substitute the point you were given (4,-2)

$- 2 = - \frac{1}{3} (4) + b$ $-2=-1/3(4)+b$

Solve for b

$- 2 = - \frac{4}{3} + b$ $-2=-4/3+b$

$- 2 + \frac{4}{3} = b$ $-2+4/3=b$

$b = - \frac{6}{3} + \frac{4}{3}$ $b=-6/3+4/3$

$b = - \frac{2}{3}$ $b=-2/3$

Now put the b into the formula

$y = - \frac{1}{3} x - \frac{2}{3}$ $y=-1/3x-2/3$

What is the slope intercept form of the line passing through (4,-2) (4,−2)(4,-2) with a slope of -1/3 −13-1/3 ?