Question

How do you find the center (h,k) and radius r of the circle with the given equation `x^2+(y-3)^2=16`?

Answer 1

Center: `(0, 3)`

Radius: `r= 4`

Explanation:

Standard form of a circle `(x-h)^2 + (y-k)^2 = r^2`
Center : `(h, k)`
Radius : `r= sqrt(r^2)`

Given `x^2 + (y-3)^2 = 16`

Or can be written as `" (x-0)^2 + (y-(3))^2 = 4^4`

Center: `(0, 3)`

Radius : 4