Question

A 10 kilogram object falls freely for a distance of 6.0 meters near Earth's surface. What is the total kinetic energy gained by the object as it falls?

Answer 1

The total kinetic energy gained is K=588.6 J

Explanation:

You find the time elapsed for the free fall with the equation
`t=sqrt(2s/g)=1.106 s`
then you find the final speed of the object `v=at=10.85m/s`
and consider the formula `dK=1/2mv^2=588.6J`