What is the inverse function of #f(x) =5x^3 + 4x^2 + 3x + 4#?
1 Answer
Explanation:
The simplest way to write the inverse function is to write
#x=5y^3+4y^2+3y+4#
This can be written explicitly (in terms of
#x=-(15 sqrt(3) sqrt(675 y^2-4576 y+7900)-675 y+2288)^(1/3)/(15 (2^(1/3)))+(29 (2^(1/3)))/(15 (15 sqrt(3) sqrt(675 y^2-4576 y+7900)-675 y+2288)^(1/3))-4/15#
Graph: