Question

For what values of x, if any, does `f(x) = 1/((x+8)(x-2))` have vertical asymptotes?

Answer 1

Vertical asymptotes at x = -8 and and x = 2

Explanation:

A graph will have vertical asymptotes when you would divide by zero. This will occur when the denominator is zero - i.e. when either of the brackets equals zero.
Solve x+8 =0 and x-2=0 for your asymptotes.