How do you find the conjugate of #(7A + 3B - 4i)#?

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Answer 1 · 2016-01-29T11:48:38

#bar(z)= (7A+3B)color(red)+4i#

Given:

#z in CC#

#z=a+ib#

the complex conjugate is

#bar(z)=acolor(red)-ib#

Same real part but opposite immaginary part.

In your case, assuming that #A,B in RR#

#:.bar(z)= (7A+3B)color(red)+4i#