If the two legs of a right triangle are 5 and 4, what is the length of the hypotenuse?

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If the two legs of a right triangle are 5 and 4, what is the length of the hypotenuse?

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Answer 1 · 2016-02-16T10:34:12

$\sqrt{41} \approx 6.4$ $sqrt41 ≈ 6.4$

Explanation:

Pythagoras' Theorem states' the square on the hypotenuse of a right angled triangle is equal to the sum of the squares on the other 2 sides'

If the hypotenuse is h , and the other 2 sides a and b , then

$h^{2} = a^{2} + b^{2}$ $h^2 = a^2 + b^2$

here a = 5 and b = 4

hence $h^{2} = 5^{2} + 4^{2} = 25 + 16 = 41$ $h^2 = 5^2 + 4^2 = 25 + 16 = 41$

now $h^{2} = 41 \Rightarrow h = \sqrt{41} \approx 6.4$ $h^2 = 41 rArr h =sqrt41 ≈ 6.4$

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If the two legs of a right triangle are 5 and 4, what is the length of the hypotenuse?

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