Question

How many moles are present in 34 grams of `Cu(OH)_2`?

Answer 1

Approx. `1/3` of a mole.

Explanation:

`"Moles of"` `Cu(OH)_2` `=` `(34*cancelg)/(97.6*cancelg*mol^-1)` `=` `??" moles"`.

How many formula units of `Cu(OH)_2` are in this quantity?

Answer 2

There are 0.348 moles in 34 grams of `Cu(OH)_2`

Explanation:

Number of moles = `Mass//Molar Mass`
Molar mass of `Cu(OH)_2`
Cu - 63.55
O - 2(16)
H - 2(1.01)
= 97.57g/mol
Thus
`34//97.57`
`= 0.348`
Thus, there are 0.348 moles in 34 grams of `Cu(OH)_2`