When both the current and voltage in a circuit are doubled, what happens to resistance and power?

1 Answer
Feb 23, 2016

Resistance remains same, but power becomes four times i.e. quadruples.

Explanation:

If current is II and voltage is VV, then resistance R=V/IR=VI and power is given by P=V*IP=VI.

As such when both the current and voltage in a circuit are doubled, resistance becomes R=(2V)/(2I)=V/IR=2V2I=VI and hence remains same.

However, power becomes P=2V*2!-4V*IP=2V2!4VI i.e. power becomes four times.