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Question #806cd

1 Answer

Feb 25, 2016

740g

Explanation:

The molecular mass of
Calcium = 40.078
Oxygen = 15.999
Hydrogen = 1.008

There are two Hydrogen atoms and two Oxygen atoms

So one mole of $C a {(O H)}_{2}$ $Ca(OH)_2$ weighs
$40.078 + 15.999 \cdot 2 + 1.008 \cdot 2 = 74.092 g$ $40.078 + 15.999*2 + 1.008*2 = 74.092g$

Therefore 10 moles weighs $740.92 g$ $740.92g$ or, rounded to the nearest 10, $740 g$ $740g$

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