Question

A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa?

Answer 1

`".06 L"`

Explanation:

Use the equation for Boyle's Law

`P_1V_1 = P_2V_2`

Plug in your values to get

`("10.1 kPa") xx (".6 L") = ("101 kPa") xx V_2`

`[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2`

`V_2 = ".06 L"`