How many atoms are present in 1.55 mol of sodium?

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How many atoms are present in 1.55 mol of sodium?

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Answer 1 · 2016-03-01T11:00:08

$9.33 \cdot 10^{23}$ $9.33*10^23$ atoms of $N a$ $Na$

Explanation:

To find the amount of atoms (or molecules) of any element, we multiply the number of mols of element with Avogadro's Number, $6.022 \cdot 10^{23}$ $6.022*10^23$

$1.55 m o l$ $1.55mol$ $N a$ $Na$ $\frac{6.022 \cdot 10^{23}}{1 m o l}$ $(6.022*10^23)/(1mol)$ = $9.33 \cdot 10^{23}$ $9.33*10^23$ atoms of $N a$ $Na$

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How many atoms are present in 1.55 mol of sodium?

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