How do you write the equation in slope intercept form given (6,2) and (2,6)?

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Answer 1 · 2016-03-04T22:36:31

#y=-x+8#

These are your points:

6#(x_1)#, 2#(y_1)# and 2#(x_2), 6##(y_2)#

To find the slope, you must do #(y_2-y_1)/(x_2-x_1)#

Here:

#(6-2)/(2-6)#

=#4/-4#

= #-1# (That's your slope!)

To find the y intercept, you must use y=mx+b and sub in one of your points.

#y=mx+b#
#y=-1x+b#
#6)=-1(2)+b#
#6=-2+b#
#6+2=b#
#8=b#

Lastly, all you have to do is plug in all of your information (your slope and y intercept). Remember: y=mx+b

#y=-x+8#