A model train, with a mass of 44 kgkg, is moving on a circular track with a radius of 33 mm. If the train's kinetic energy changes from 1212 JJ to 4848 JJ, by how much will the centripetal force applied by the tracks change by?

1 Answer

Centripetal force changes from 8N8N to 32N32N

Explanation:

Kinetic energy KK of an object with mass mm moving at a velocity of vv is given by 1/2mv^212mv2. When Kinetic energy increases 48/12=44812=4 times, velocity is hence doubled.

The initial velocity will be given by v=sqrt(2K/m)=sqrt(2xx12/4)=sqrt6v=2Km=2×124=6 and it will become 2sqrt626 after increase in kinetic energy.

When an object moves in a circular path at a constant speed, it experiences a centripetal force is given by F=mv^2/rF=mv2r, where: FF is centripetal force, mm is mass, vv is velocity and rr is radius of circular path. As there is no change in mass and radius and centripetal force is also proportional to square of velocity,

Centripetal force at the beginning will be 4xx(sqrt6)^2/34×(6)23 or 8N8N and this becomes 4xx(2sqrt6)^2/34×(26)23 or 32N32N.

Hence centripetal force changes from 8N8N to 32N32N