How would you calculate the speed at which the moon revolves around the earth in m/s?

1 Answer

speed equals orbital radius times the orbital angular speed

Explanation:

The moon is 384,000 km away from the Earth. It revolves around the earth in 27.3 days.

it's speed is : v = r omega = r (2pi)/T=\frac{2\pi.r}{T}v=rω=r2πT=2π.rT,

where TT is the lunar orbital period, and rr the orbital radius of moon (the moon follows an ellipse but the eccentricity is small enough that you can treat it as a circle.)

This gives you,

v = (384,000 \quad km)\times (2pi)/((27.3\quad days)\times (86400\quad s/(day)))
= 1.023 \quad(km)/s