Question

The force applied against an object moving horizontally on a linear path is described by `F(x)=x^3+ 3`. By how much does the object's kinetic energy change as the object moves from `x in [ 3, 5 ]`?

Answer 1

Use Work Energy Theorem:
`W_F = DeltaKE = [(x(x^3-12))/4]_3^5 = 130J`

Explanation:

Use Work Energy Theorem:
`W_F = DeltaKE = 1/2mDeltav^2`
Now `W_F = intF*dr = int_3^5 F*dx = int_3^5 x^3+3*dx`
`W_F = [(x(x^3-12))/4]_3^5 = 130J`