How do you graph the inequality y<2/3x + 3y<23x+3?

1 Answer
Wayne
Mar 13, 2016

The slope is (2/3)(23) and the y-intercept is 33
graph{y<(2/3)x+3 [-10, 10, -5, 5]}

Explanation:

The inequality is already written in the slope/intercept form, y=mx+b, where mm is the slope of the line and bb is the y-intecept. Since you are dealing with the inequality <<, the graph is everything below and not including the line y=(2/3)x +3y=(23)x+3. Therefore shade the region below the broken line, which shows that the line is not included in the solution.

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