How do you solve and graph $6[5y-(3y-1)]≥4(3y-7)$ ?

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Answer 1 · 2016-03-19T15:12:24

Inequality has infinite solution. Entire real number line (if that is the domain) is the graph for the inequality.

$6(5y - 3y + 1) >=12y - 28$

$30y - 18y + 6 >= 12y - 28$

$12y - 12y >= -28 - 6$

$0y >= -34$

$0 >= -34$

As this is true for all $y$ , the inequality is true for all $y$ and hence has infinite solutions.

Further, as all $y$ satisfy the inequality, entire real number line (if that is the domain) is the graph of the inequality

How do you solve and graph 6[5y-(3y-1)]≥4(3y-7)6[5y-(3y-1)]≥4(3y-7)?