Question

How many grams of `Cr(NO_3)_2` are in 8.4 mole?

Answer 1

Chromous nitrate, `Cr(NO_3)_2`, has a formula weight of `176.01` `g*mol`

Explanation:

You have an `8.4` `mol` quantity, which has a mass of `8.4*cancel(mol)xx176.01*g*cancel(mol^-1)` `~=` `1.5` `kg`.

Answer 2

Hi there!

With `Cr(NO_3)_2`, there is approximately 1460.97 g in 8.3 moles.

Explanation:

To figure this out, note the relationship between mass, molar mass and moles whereby:

n (moles) = mass/molar mass...

or if you're more of a visual oriented learner, I will show the unit conversion/dimensional analysis method! Either will work!

Let's start off with what you're given:

n = 8.3
m (mass in grams) = ?
M (molar mass) = `Cr(NO_3)_2 = (52.00 g/(mol)+)2((14.01 g/(mol))+3(16.00g/(mol)))`

`M = 176.02 g/(mol)`

Now you know n and M, you can find m using the aforementioned expression! Substituting in you get:

`8.3 = m/(176.02)`

`m = (8.3)(176.02)`

`m = 1460.97 g`

You can also use unit conversion/dimensional analysis whereby:

`8.3 mol * 176.02 g/(mol) ->` Moles cancel and you're left with:

`1460.97 g`

Therefore, in 8.3 moles of `Cr(NO_3)_2`, there is approximately 1460.97 g! Hopefully this was helpful! If you have any questions, let me know! :)