Question

The force applied against a moving object travelling on a linear path is given by `F(x)= sinx + 2`. How much work would it take to move the object over `x in [ 0,pi/3]`?

Answer 1

`1/2+2*pi/3` Joules

Explanation:

The work necessary is `dW=F(x)*dx`

as the movement is between 0 and 3 metres

`W=int_0^3 F(x) dx = int_0^3 (senx + 2) dx =1/2+2*pi/3` due to

`cos(pi/3) = 1/2`